这篇文章主要为大家详细介绍了C++实现简单校园导游系统,文中示例代码介绍的非常详细,具有一定的参考价值,感兴趣的小伙伴们可以参考一下
本文实例为大家分享了C++实现校园导游系统的具体代码,供大家参考,具体内容如下
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//password为后台管理的登录密码 FILE *fp; char na[100]; char str1[100],str3[100]; int N,M; int a[100][100]; using namespace std; typedef struct { int num; char name[100]; char introduction[100]; } VertexType; typedef struct { int edges[100][100]; int n,e; VertexType vex[100]; } MGraph; typedef struct ANode { int adjvex; struct ANode *nextarc; } ArcNode; typedef struct Vnode { ArcNode *firstarc; } VNode; typedef VNode AdjList[100]; typedef struct { AdjList adjlist; int n,e; } ALGraph; MGraph g; //将文本文件打开并输出文件中的内容 void ReadData1(MGraph &g) { M=N; FILE *fp; int i = 0,j; if ((fp= fopen ( "path.txt" , "r" ))==NULL) { printf ( "error open!" ); exit (0); } for (i=0; i<M; i++) { for (j=0; j<M; j++) { fscanf (fp, "%d" ,&g.edges[i][j]); } } fclose (fp); } void WriteData1(MGraph &g) { FILE *fp; int i = 0,j; if ((fp= fopen ( "path.txt" , "w" ))==NULL) { printf ( "error open!" ); exit (0); } for (i=0; i<N; i++) { for (j=0; j<N; j++) { printf ( "%d " ,g.edges[i][j]); fprintf (fp, "%d " ,g.edges[i][j]); } fprintf (fp, "\n" ); printf ( "\n" ); } fclose (fp); } void ReadData(MGraph &g) { FILE *fp; int i = 0; if ((fp= fopen ( "data.txt" , "r" ))==NULL) { printf ( "error open!" ); exit (0); } while ( fscanf (fp, "%d %s %s" ,&g.vex[i].num,g.vex[i].name,g.vex[i].introduction)!= EOF) { i++; } N = i; fclose (fp); return ; } void WriteData(MGraph &g) { FILE *fp; int i=0; if ((fp= fopen ( "data.txt" , "w" ))==NULL) { printf ( "error open!" ); exit (0); } for (i=0; i<N; i++) fprintf (fp, "%d %s %s\n" ,g.vex[i].num,g.vex[i].name,g.vex[i].introduction); fclose (fp); } //将邻接矩阵改为邻接表 void MatToList(MGraph g,ALGraph *&G) { int i,j; ArcNode *p; G=(ALGraph *) malloc ( sizeof (ALGraph)); for (i=0; i<g.n; i++) G->adjlist[i].firstarc=NULL; for (i=0; i<g.n; i++) for (j=g.n-1; j>=0; j--) { if (g.edges[i][j]!=INF) { p=(ArcNode *) malloc ( sizeof (ArcNode)); p->adjvex=j; p->nextarc=G->adjlist[i].firstarc; G->adjlist[i].firstarc=p; } } G->n=g.n; G->e=g.e; } //查找相应景点的介绍 void FindIntroduction(MGraph &g) { int x,d; while (1) { printf ( "请输入要查询的景点的编号:" ); scanf ( "%d" ,&x); ReadData(g); printf ( "景点的名称:%s\n" ,g.vex[x].name); printf ( "景点的简介:" ); printf ( "%s\n" ,g.vex[x].introduction); printf ( "是否要继续查询(0.继续 1.不继续):" ); scanf ( "%d" ,&d); while (1) { if (d==0||d==1) break ; else { printf ( "输入的数据不合理,请重新输入:" ); scanf ( "%d" ,&d); } } if (d==0) continue ; else break ; } } //输出两个顶点间的最短路径 void Dispath(MGraph &g, int A[][100], int path[][100]) { int i,j,k,s,u,v; printf ( "请输入你所在位置的编号:" ); scanf ( "%d" ,&u); printf ( "请输入你要去位置的编号:" ); scanf ( "%d" ,&v); int apath[100],d; for (i=0; i<g.n; i++) { for (j=0; j<g.n; j++) { if (A[i][j]!=INF&&i!=j&&u==i&&v==j) { printf ( " 从%s到%s的最短路径为:" ,g.vex[i].name,g.vex[j].name); k=path[i][j]; d=0; apath[d]=j; while (k!=-1&&k!=i) { d++; apath[d]=k; k=path[i][k]; } d++; apath[d]=i; printf ( "%s" ,g.vex[apath[d]].name); for (s=d-1; s>=0; s--) printf ( "->%s" ,g.vex[apath[s]].name); printf ( "\n" ); printf ( " 路径长度为:%d" ,A[i][j]); printf ( "\n" ); } } } } //查找两顶点间的最短路径 void FindMinPath(MGraph &g) { int A[100][100],path[100][100]; int i,j,k; for (i=0; i<g.n; i++) { for (j=0; j<g.n; j++) { A[i][j]=g.edges[i][j]; if (i!=j&&g.edges[i][j]<INF) path[i][j]=i; else path[i][j]=-1; } } for (k=0; k<g.n; k++) { for (i=0; i<g.n; i++) { for (j=0; j<g.n; j++) { if (A[i][j]>A[k][j]+A[i][k]) { A[i][j]=A[k][j]+A[i][k]; path[i][j]=path[k][j]; } } } } Dispath(g,A,path); } //查找两顶点间的所有路径 void FindaPath(MGraph &g,ALGraph *G, int u, int v, int path[], int d) { int w,i; ArcNode *p; visited[u]=1; d++; path[d]=u; if (u==v&&d>=1) { printf ( " " ); for (i=0; i<d; i++) printf ( "%s->" ,g.vex[path[i]].name); printf ( "%s" ,g.vex[path[d]].name); printf ( "\n" ); } p=G->adjlist[u].firstarc; while (p!=NULL) { w=p->adjvex; if (visited[w]==0) FindaPath(g,G,w,v,path,d); p=p->nextarc; } visited[u]=0; } //删除景点简介信息 void delete_str( char str1[], char str2[], int len, char str3[]) { int num=0,k=0,i=0,j=0; //num用来记录子串的个数 k用来记录子串的位置 char *p=str2; //使用p还原str到初始位置 while (str1[i]!= '\0' ) { if (str1[i]!=str2[j]) { str3[k++]=str1[i++]; //当str1中的字符与str的首字符不相同时 } else { char *temp=str2; for (; (str1[i]==str2[j])&&str2[j]!= '\0' ; j++) { i++; } if (j==len) { num++; //出现重复子串,num加一 } else { //主字符串中存在和子串前几个字符相同的一段字符 //退出循环并将这段字符写进新的字符数组中 for ( int m=0; m<j; m++) { str3[k++]=temp[m]; } } str2=p; j=0; } } } //密码输入函数 int inputpassword() { char a[10]; int pass=0; int i; while (1) { for (i=0; i<6; i++) { a[i]=getch(); putchar ( '*' ); if (a[i]>= '0' &&a[i]<= '9' ) pass=pass*10+a[i]- '0' ; else if (a[i]== '\b' ) //当遇到退格键不做处理 { printf ( "\b \b" ); i--; } else { pass=0; break ; //退出for循环后,再次接受 } } fflush (stdin); //清除键盘缓存区中已经有的输入 printf ( "\n" ); if (pass==0) //此条件成立可能由两种情况引起:输入了非数字字符被直接重置为0,或6位全0后正常退出for循环 { printf ( "密码要求全为数字,且不能全0!\n" ); printf ( "请重新输入密码: " ); } else break ; } return pass; } //在图中增加一个顶点 void add_point(MGraph &g) { int i,d; N++; g.vex[N-1].num=N-1; printf ( "%d\n" ,N); printf ( "请输入要增加景点的名称:" ); scanf ( "%s" ,g.vex[N-1].name); printf ( "%s\n" ,g.vex[N-1].name); printf ( "请输入该景点与其它景点间的路径长度:" ); for (i=0; i<N; i++) { scanf ( "%d" ,&d); g.edges[i][N-1]=g.edges[N-1][i]=d; } printf ( "请输入要增加顶点的简介:" ); scanf ( "%s" ,g.vex[N-1].introduction); printf ( "增加成功!\n" ); } //在图中增加一条路径 void add_path(MGraph &g) { int i,j,length,k; do { printf ( "请输入要增加路径的起始点的编号:" ); scanf ( "%d" ,&i); printf ( "请输入要增加路径的终点的编号:" ); scanf ( "%d" ,&j); if (i>=0&&i<=N-1&&j>=0&&j<=N-1&&j>=0) { if (g.edges[i][j]!=INF&&g.edges[j][i]!=INF) { printf ( "该两点之间已存在路径,是否进行修改(0.修改 1.不修改):" ); scanf ( "%d" ,&k); if (k==0) { printf ( "请输入要修改的路径的长度:" ); scanf ( "%d" ,&length); g.edges[j][i]=g.edges[i][j]=length; printf ( "修改成功!" ); } else g.edges[j][i]=g.edges[i][j]; } else { printf ( "请输入要增加的路径的长度:" ); scanf ( "%d" ,&length); g.edges[j][i]=g.edges[i][j]=length; printf ( "添加成功!\n" ); } break ; } else { printf ( "输入的顶点在原图中不存在!\n" ); continue ; } } while (1); } //删除图中的一个顶点 void delete_point(MGraph &g) { int i,j,m; printf ( "%d\n" ,N); printf ( "请输入要删除景点的编号:" ); scanf ( "%d" ,&m); do { if (m>=0&&m<=N-1) break ; else { printf ( "请输入要删除景点的编号:" ); scanf ( "%d" ,&m); } } while (1); for (i=0; i<M; i++) { for (j=0; j<M; j++) { if (g.edges[m][j]!=INF&&g.edges[i][m]!=INF) g.edges[m][j]=g.edges[i][m]=INF; } } g.vex[m].num=INF; strcpy (g.vex[m].name, "F" ); printf ( "删除成功!\n" ); } //删除图中的一条路径 void delete_path(MGraph &g) { int i,j; do { printf ( "请输入要删除路径的起始点的编号:" ); scanf ( "%d" ,&i); printf ( "请输入要删除路径的终点的编号:" ); scanf ( "%d" ,&j); if (g.edges[i][j]==INF) printf ( "这两点间不存在路径!\n" ); else { g.edges[i][j]=g.edges[j][i]=INF; break ; } } while (1); printf ( "删除成功!\n" ); } //整个程序的驱动 void function() { ALGraph *G; int i,j,u,v,path[100],x,k,l,d,y; int ch,pass; char str2[500],nam[100]; g.n=10; g.e=18; ReadData(g); ReadData1(g); MatToList(g,G); for (i=0; i<G->n; i++) visited[i]=0; system ( "color F0" ); printf ( "\t\t *******************************\n" ); printf ( "\t\t * 1.用户 *\n" ); printf ( "\t\t * 2.管理人员 *\n" ); printf ( "\t\t *******************************\n" ); printf ( "请选择相应的编号进行下一步操作:" ); scanf ( "%d" ,&k); do { if (k==1||k==2) break ; else { printf ( "输入数据不合理,请重新输入:" ); scanf ( "%d" ,&k); } } while (1); if (k==1) { system ( "title 校园景点介绍及路径查询系统" ); system ( "color F0" ); printf ( "\n\n\n\n\n\n\n\n\n\n\n\n" ); printf ( "\t\t\t欢迎进入校园景点介绍及路径查询系统!\n\n\n\n\n\n\n\n\n\n\n\n\n" ); printf ( "正在进入,请稍后...\n" ); printf ( "===============================================================================\r" ); for (j=0; j<80; j++) { Sleep(50); printf ( ">" ); } system ( "cls" ); do { printf ( "\t\t *******************************\n" ); printf ( "\t\t * 1.景点简介 *\n" ); printf ( "\t\t * 2.两景点间最短路径 *\n" ); printf ( "\t\t * 3.两景点间所有路径 *\n" ); printf ( "\t\t * 4.退出系统 *\n" ); printf ( "\t\t *******************************\n" ); printf ( "请输入要进行的操作的编号:" ); scanf ( "%d" ,&x); do { if (x>=1&&x<=4) break ; else { printf ( "输入数据不合理,请重新输入:" ); scanf ( "%d" ,&x); } } while (1); if (x>=1&&x<=3) { printf ( "\t\t *******************************\n" ); if (N%2!=0) { for (i=0; i<N-1; i+=2) { printf ( "\t\t %d.%s \t%d.%s \n" ,g.vex[i].num,g.vex[i].name,g.vex[i+1].num,g.vex[i+1].name); } printf ( "\t\t %d.%s \n" ,g.vex[i].num,g.vex[i+1].name); } else { for (i=0; i<N; i+=2) { printf ( "\t\t %d.%s \t%d.%s \n" ,g.vex[i].num,g.vex[i].name,g.vex[i+1].num,g.vex[i+1].name); } } printf ( "\t\t *******************************\n" ); printf ( "%d" ,11); } switch (x) { case 1: ReadData(g); FindIntroduction(g); system ( "cls" ); break ; case 2: ReadData(g); do { FindMinPath(g); printf ( "是否继续进行该操作(0.继续 1.不继续):" ); scanf ( "%d" ,&y); if (y==1) break ; else continue ; } while (1); system ( "pause" ); system ( "cls" ); break ; case 3: ReadData(g); do { printf ( "请输入起点位置的编号:" ); scanf ( "%d" ,&u); printf ( "请输入终点位置的编号:" ); scanf ( "%d" ,&v); printf ( "从%s到%s的所有路径为:\n" ,g.vex[u].name,g.vex[v].name); FindaPath(g,G,u,v,path,-1); printf ( "是否继续进行该操作(0.继续 1.不继续):" ); scanf ( "%d" ,&y); if (y==1) break ; else continue ; } while (1); system ( "pause" ); system ( "cls" ); break ; case 4: printf ( "确认退出吗(0.退出 1.不退出):" ); scanf ( "%d" ,&ch); while (1) { if (ch==0||ch==1) break ; else { printf ( "输入的数据不合理,请重新输入:" ); scanf ( "%d" ,&ch); } } if (ch==0) { x=0; printf ( "谢谢使用本系统,欢迎下次光临!" ); } else { continue ; } } } while (x!=0); } else { printf ( "请输入管理代号:" ); scanf ( "%s" ,na); printf ( "请输入管理登录密码:" ); password=inputpassword(); FILE *fp1; if ((fp1= fopen ( "password.txt" , "r" ))==NULL) { printf ( "Cannot open the file!" ); exit (0); } fscanf (fp1, "%s %d" ,nam,&pass); fclose (fp1); int t=3; do { if (password!=pass) { t--; if (t==0) { printf ( "你已经输错三次密码,系统将于10秒后关闭!" ); Sleep(10000); break ; } printf ( "输入的密码错误!你还有%d次机会,请重新输入:" ,t); password=inputpassword(); } else break ; } while (t!=0); system ( "cls" ); if (password==pass&& strcmp (nam,na)==0) { do { printf ( "\t\t *******************************\n" ); printf ( "\t\t * 1.增加景点简介信息 *\n" ); printf ( "\t\t * 2.删除景点简介信息 *\n" ); printf ( "\t\t * 3.更新景点简介信息 *\n" ); printf ( "\t\t * 4.增加景点 *\n" ); printf ( "\t\t * 5.增加路径 *\n" ); printf ( "\t\t * 6.删除景点 *\n" ); printf ( "\t\t * 7.删除路径 *\n" ); printf ( "\t\t * 8.退出系统 *\n" ); printf ( "\t\t *******************************\n" ); printf ( "请选择要进行的操作:" ); scanf ( "%d" ,&l); printf ( "\t\t *******************************\n" ); if (N%2!=0) { for (i=0; i<N-1; i+=2) { printf ( "\t\t %d.%s \t%d.%s \n" ,g.vex[i].num,g.vex[i].name,g.vex[i+1].num,g.vex[i+1].name); } printf ( "\t\t %d.%s \n" ,g.vex[i].num,g.vex[i].name); } else { for (i=0; i<N; i+=2) { printf ( "\t\t %d.%s \t%d.%s \n" ,g.vex[i].num,g.vex[i].name,g.vex[i+1].num,g.vex[i+1].name); } } printf ( "\t\t *******************************\n" ); if (l==1) { do { printf ( "请输入要要增加信息的景点的编号:" ); scanf ( "%d" ,&d); ReadData(g); printf ( "%s\n" ,g.vex[d].introduction); printf ( "请输入要增加的信息:" ); scanf ( "%s" ,str2); strcat (g.vex[d].introduction,str2); printf ( "增加成功!\n" ); WriteData(g); printf ( "是否继续进行该操作(0.继续 1.不继续):" ); scanf ( "%d" ,&y); if (y==1) break ; else continue ; } while (1); system ( "cls" ); } if (l==2) { do { printf ( "请输入要删除信息的景点的编号:" ); scanf ( "%d" ,&d); ReadData(g); strcpy (str1,g.vex[d].introduction); printf ( "%s\n" ,str1); printf ( "请输入要删除的信息:" ); scanf ( "%s" ,str2); printf ( "%d\n" ,N); delete_str(str1,str2, strlen (str2),str3); printf ( "%s\n" ,str3); strcpy (g.vex[d].introduction,str3); printf ( "%s\n" ,g.vex[d].introduction); WriteData(g); printf ( "删除成功!\n" ); printf ( "是否继续进行该操作(0.继续 1.不继续):" ); scanf ( "%d" ,&y); if (y==1) break ; else continue ; } while (1); system ( "cls" ); } if (l==3) { do { printf ( "请输入要更新信息的景点的编号:" ); scanf ( "%d" ,&d); ReadData(g); printf ( "请输入要更新的信息:" ); scanf ( "%s" ,str2); strcpy (g.vex[d].introduction,str2); WriteData(g); printf ( "是否继续进行该操作(0.继续 1.不继续):" ); scanf ( "%d" ,&y); if (y==1) break ; else continue ; } while (1); system ( "cls" ); } if (l==4) { ReadData(g); ReadData1(g); for (i=0; i<N; i++) { for (j=0; j<N; j++) { printf ( "%d " ,g.edges[i][j]); } printf ( "\n" ); } add_point(g); WriteData1(g); WriteData(g); } if (l==5) { ReadData1(g); for (i=0; i<M; i++) { for (j=0; j<M; j++) { printf ( "%d " ,g.edges[i][j]); } printf ( "\n" ); } add_path(g); WriteData1(g); } if (l==6) { ReadData(g); ReadData1(g); for (i=0; i<M; i++) { for (j=0; j<M; j++) { printf ( "%d " ,g.edges[i][j]); } printf ( "\n" ); } delete_point(g); WriteData1(g); WriteData(g); } if (l==7) { ReadData1(g); for (i=0; i<M; i++) { for (j=0; j<M; j++) { printf ( "%d " ,g.edges[i][j]); } printf ( "\n" ); } delete_path(g); WriteData1(g); } if (l==8) { printf ( "确认退出吗(0.退出 1.不退出):" ); scanf ( "%d" ,&ch); while (1) { if (ch==0||ch==1) break ; else { printf ( "输入的数据不合理,请重新输入:" ); scanf ( "%d" ,&ch); } } if (ch==0) { x=0; printf ( "正在退出...." ); Sleep(5000); break ; } else { continue ; } } } while (1); } } } int main() { function(); return 0; } |
需要的文件:
path.txt的内容:
1 2 3 4 5 6 7 8 9 10 | 0 20 60 150 32767 60 32767 100 300 150 20 0 50 100 32767 32767 32767 32767 32767 32767 60 50 0 32767 32767 300 40 32767 32767 32767 150 100 32767 0 32767 32767 32767 100 32767 32767 32767 32767 32767 32767 0 50 32767 32767 32767 30 60 32767 300 32767 32767 0 200 32767 32767 50 32767 32767 40 32767 32767 200 0 32767 32767 32767 100 32767 100 32767 32767 32767 0 50 32767 32767 300 32767 32767 32767 32767 32767 32767 50 0 350 50 32767 32767 32767 30 50 32767 32767 350 |
password.txt的内容:
1 | pass 123456 |
data.txt的内容:
1 2 3 4 5 6 7 8 9 10 | 0 三元湖 烟大的一道靓丽的风景 1 钟楼 配备有专业设备的实验综合楼 2 八景园 休息和聊天的好去处 3 小树林 各种社团的活动场所, 4 九龙广场 海豚雕塑加上美丽的喷泉很漂亮 5 八餐 美味的饭菜让人回味无穷 6 一餐 豪华的装修,美味的饭菜 7 体育场 锻炼和饭后散步的好去处 8 七餐 全亚洲最大的学生餐厅 9 新图 藏书丰富,安静的环境让人很舒服 |
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